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It would make more sense to preserve the ratio if possible.
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Yeah, this concept is interesting but the fact that the simplest test case gives what's fundamentally a surprising result is very annoying.

It also doesn't help that in the example, the expected outcome of 53.3333/46.6667 isn't even considered.

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You can do this with bidicalc already! You just have to model the problem correctly. If you expect the ratio to remain constant, what you actually want is a problem with a single free variable: the scale.

    A1 = 1.0       // the scale, your variable
    A2 = 6 * A1    // intermediate values
    A3 = 8 * A1 
    A4 = A2 + A3   // the sum
Now update A4 (or any other cell!) and the scale (A1, the only variable) will update as you expect.
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To get that, you could pass the ratio explicitly. C = 5A + 7B
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What is inputs a,b,c,d,and e are polynomial coefficients? I am hoping to get a fields medal plz respond.
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You can actually solve fifth order polynomials with bidicalc! But it's a numerical solution, not an algebraic one, so no Fields medal.
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I think it would be good if you could lock one of them.
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You can.
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With # (octothorpe) #Val
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