I'd be interested in seeing an explanation of the code, since it looks pretty incomprehensible to me. Per the arbitrary rules I set for myself, I'm not allowed to precompute/hardcode the wheel (looks like this implementation uses a hardcoded wheel of size 2x3x5=30). I wonder if/by how much the performance would suffer by computing and storing the coprime remainders in memory instead of handing them directly to the compiler.
replyI wrote this in a semi obfuscated style to make it fit on one screen.
It's indeed a hardcoded 2x3x5 wheel; but I suspect computing all those
constants would have made the program significantly longer.
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