If you add 5.1kΩ pulldown resistors on the CC lines for USB-C, you can get the standard 5V without a handshake although current may be limited by some chargers without negotiation.
replyI think you're overstating this. The "handshake" is purely 2 simple resistors correctly installed. The problem is a lot of folks do it wrong for various reasons, most likely never testing with anything more than type a to type c cables.
replyhttps://people.kernel.org/bleung/how-to-design-a-proper-usb-...
One of the many deficiencies of usb-c (who knows what power your cable supports, charger supports, if you accessory will charge, of it will connect at all)
replyInteresting. Does UsBC spec/licensing require any sort of notation for products that don’t implement handshake?
replyThere is no handshake, all that's needed are two 5.1 kΩ pulldown resistors. By omitting them the manufacturer saved all of about 0.1c and made their device incompatible with compliant usb-c chargers.
replyMore info: https://hackaday.com/2023/02/07/all-about-usb-c-manufacturer...