You can do a pilot test of solar panels anywhere and call it a success, but the real test is scaling it up in an economically viable way compared to alternatives. None of that was tested.
Putting panels in a line is the worst arrangement. Just put them on roof tops or fields and keep it to places where they don’t have to be armored and reinforced.
However, I agree that putting solar panels in between or near rails will increase the cost of maintenance: the technicians will need to travel longer times to the work site, and now they also need to be certified to work near railroads.
Just normal-ass solar is already safe proven and effective. Why do we need to remix it when there are still so many easy wins to be achieved?
Should have many of the same drawbacks, with 2 big differences:
1. Trains not driving directly on the panels' surface (which makes solar roadways a bad idea in any case). And
2. Trains on their own track, so the 'road surface' conditions of the panels (rain, snow etc) don't matter safety-wise.
That said: imho there's still so many spaces better suited to put solar panels, that between train tracks is among the last places I'd go for. Especially if it requires custom-design panels.
If there's a single downside I'm not sure what it is.
Before I read the article I was thinking the electricity from the panels would power the trains but doesn't sound like the output is enough.
> in one year, the project has produced around 16,000 kWh.
160 kWh per meter.
Urban Metro / Trams: 2 to 10 kWh/km
Commuter Trains (EMUs): 4 to 12 kWh/km
Regional / Intercity Trains: 6 to 20 kWh/km
High-Speed Trains: 15 to 60 kWh/km
Freight Locomotives: 10 to 50+ kWh/kmI didn't try to calculate the amount of energy it produces in a year, just the length of panels required to power a high speed train when the sun is shining. 18,000 watts / 100 meters is 180 watts per meter. At 180 watts per meter, 50 km gives you 9 MW, which is about what a high speed train consumes at cruise.
This is incorrect. 18000 Wp/100m = 180 Wp/m or 180 kWp/km. So parent is correct, and you can either add or drop a "k".
That is peak power, obtainable in summer months & muuch less in winter.
Over the whole year: 16000 kWh/100m = 160 kWh/m = 160 MWh (160,000 kWh) per km.